Math for Grade 9
1 Number Systems
1-1 Introduction to Real Numbers
1-2 Rational Numbers
1-3 Irrational Numbers
1-4 Properties of Real Numbers
1-5 Operations with Real Numbers
1-6 Square Roots and Cube Roots
1-7 Approximation and Estimation
2 Algebra
2-1 Algebraic Expressions
2-2 Polynomials
2-3 Factorization of Polynomials
2-4 Linear Equations in One Variable
2-5 Simultaneous Linear Equations
2-6 Quadratic Equations
2-7 Inequalities
2-8 Algebraic Fractions
3 Geometry
3-1 Lines and Angles
3-2 Triangles
3-3 Congruence and Similarity
3-4 Pythagoras Theorem
3-5 Quadrilaterals
3-6 Circles
3-7 Coordinate Geometry
3-8 Transformations
4 Mensuration
4-1 Perimeter and Area of Plane Figures
4-2 Surface Area and Volume of Solids
4-3 Applications of Mensuration
5 Statistics and Probability
5-1 Collection and Organization of Data
5-2 Measures of Central Tendency
5-3 Graphical Representation of Data
5-4 Probability Concepts
5-5 Simple Probability Problems
Pythagoras Theorem - Grade 9 Math

Pythagoras Theorem - Grade 9 Math

Key Concepts

1. Definition of Pythagoras Theorem

Pythagoras Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. Mathematically, it is expressed as:

\(a^2 + b^2 = c^2\)

where \(a\) and \(b\) are the lengths of the legs of the triangle, and \(c\) is the length of the hypotenuse.

2. Application of Pythagoras Theorem

The theorem is used to find the length of any side of a right-angled triangle when the lengths of the other two sides are known. It is also used in various real-world applications, such as construction, navigation, and physics.

3. Special Triangles

Certain right-angled triangles have specific side lengths that are commonly used in problems. For example, the 3-4-5 triangle is a special right-angled triangle where the sides are in the ratio 3:4:5. This ratio is often used to simplify calculations.

Detailed Explanation

Example 1: Using Pythagoras Theorem to Find the Hypotenuse

Problem: Find the length of the hypotenuse of a right-angled triangle with legs of lengths 6 cm and 8 cm.

Solution:

Using the Pythagoras Theorem:

\(a = 6\), \(b = 8\)

\(c^2 = a^2 + b^2\)

\(c^2 = 6^2 + 8^2\)

\(c^2 = 36 + 64\)

\(c^2 = 100\)

\(c = \sqrt{100}\)

\(c = 10\)

The length of the hypotenuse is 10 cm.

Example 2: Using Pythagoras Theorem to Find a Leg

Problem: Find the length of one leg of a right-angled triangle with a hypotenuse of 13 cm and the other leg of 5 cm.

Solution:

Using the Pythagoras Theorem:

\(c = 13\), \(a = 5\)

\(c^2 = a^2 + b^2\)

\(13^2 = 5^2 + b^2\)

\(169 = 25 + b^2\)

\(b^2 = 169 - 25\)

\(b^2 = 144\)

\(b = \sqrt{144}\)

\(b = 12\)

The length of the other leg is 12 cm.

Example 3: Special Triangles - 3-4-5 Triangle

Problem: Verify the Pythagoras Theorem for a 3-4-5 triangle.

Solution:

For a 3-4-5 triangle:

\(a = 3\), \(b = 4\), \(c = 5\)

Using the Pythagoras Theorem:

\(c^2 = a^2 + b^2\)

\(5^2 = 3^2 + 4^2\)

\(25 = 9 + 16\)

\(25 = 25\)

The equation holds true, verifying the Pythagoras Theorem for a 3-4-5 triangle.

Analogies for Clarity

Pythagoras Theorem as a Puzzle

Think of the Pythagoras Theorem as a puzzle where you need to fit three squares together. The largest square (hypotenuse) is made by combining the areas of the two smaller squares (legs). Solving the puzzle means finding the correct side lengths that fit perfectly together.

Pythagoras Theorem as a Bridge

Consider the theorem as a bridge that connects the lengths of the sides of a right-angled triangle. The bridge ensures that the relationship between the sides is always balanced, allowing you to cross from knowing two sides to finding the third.